chiques
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The smith chart for that cap shows you that at 205MHz it is 10pF ( 77 ohm ) and 50 ohm resistive ...
impedance is 77.16 Ohm? Do I use this as the reactance (Xc)?
When there is negligible ohmic resistance, it's true that the capacitive reactance formula tells the impedance.
However if the resistor value is increased, it changes the situation so that C needs to be adjusted to a different value.
It was a simple question that nobody could explain clearly. I'm sorry you were confused.Why do you confuse people if you don't understand the Smith Chart, and how to read it?
The original question was clear: 50.04 -j77.16
In addition however is a formula which complicates things: √(R^2 + XC^2).
Are you new to the concept of complex impedance?
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