I see the real part (50Ohm) and the impedance in the imaginary part (77 Ohm).The smith chart for that cap shows you that at 205MHz it is 10pF ( 77 ohm ) and 50 ohm resistive ...
Why do you confuse people if you don't understand the Smith Chart, and how to read it?When there is negligible ohmic resistance, it's true that the capacitive reactance formula tells the impedance.
However if the resistor value is increased, it changes the situation so that C needs to be adjusted to a different value.
Are you new to the concept of complex impedance? In the original post, there is a proper specification of complex impedance (real part from 50 Ohm termination, imaginary part from capacitor) so I'm a bit confused what you are trying to discuss (or show) here.In addition however is a formula which complicates things: √(R^2 + XC^2).
Even if I were experienced at calculations with imaginary numbers and complex impedances, it's obvious I would need to learn more in order to account for the results of my Wheatstone bridge experiment (post #15). Isn't there more than meets the eye here?Are you new to the concept of complex impedance?