Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronic Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

Register Log in

Bandwidh of fm signal when squared...

Status
Not open for further replies.

rsashwinkumar

Member level 4
Joined
Jun 25, 2011
Messages
70
Helped
11
Reputation
22
Reaction score
11
Trophy points
1,288
Activity points
1,825
Given an FM signal with frequency deviation 90kHz and modulating signal frequency of 5kHz. The B.W. of the FM signal can be found using Carson's rule. Now my problem is what happens to the B.W. when the FM signal is squared and cubed?? Plz help me out...
 

FvM

Super Moderator
Staff member
Joined
Jan 22, 2008
Messages
47,663
Helped
14,075
Reputation
28,407
Reaction score
12,742
Trophy points
1,393
Location
Bochum, Germany
Activity points
276,908
Generally, each of the generated nth order harmonics will show an n-fold modulation bandwidth.
 

Miguel Gaspar

Advanced Member level 1
Joined
Mar 6, 2006
Messages
479
Helped
70
Reputation
140
Reaction score
34
Trophy points
1,308
Location
Culiacán, Sinaloa, Mexico
Activity points
4,971
First you must use the bessel function to determine the center, the minimum and the maximum frecuency of your FM signal.
Second you must use the Modulation Theorem (FOURIER), to determine the new BW

L{f(t) COSωot} = ½ [F(ω-ωo)+F(ω+ωo)]
where ω is the frecuency of f(f), ωo the frecuency of the cos function
F is the fourier transfor of the ft)

In your case f min and fmax and both signals are equal so
new fmin (squared signal) = ωmin - ωmin
new fmax (squared signal) = ωmax + ωmax
BW = new fmax (squared signal) - new fmin (squared signal)

repeat the process for a cubic case
 

Status
Not open for further replies.
Toggle Sidebar

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Top