Arithnmatic operation in Hitech C

[prasad70]

Can some one please explain how below expression can be written in C (Prefer Hitech c) ?

Y = 250000/(X^2.93)

regards

 

[GSM Man]

You can write that in Standard C using any compiler that supports floating point numbers.

#include <math.h>
.
.
.
double X, Y;

X = 10;
Y = 250000 / pow(X, 2.93);

 

[jayanth.devarayanadurga]

If you have pow() function in Hi Tech C then you can use that also but remember to include math.h file.

Y = (250000) / pow(X,2.93);

 

[prasad70]

can I get the links/sites where i can learn how mathmatical expression can be used in C.

thks

 

[sky_123]

It's got nothing to do with C. The math library is a library supplied with your compiler. Therefore, you need to check the library documentation that your compiler vendor must have supplied to you.
**broken link removed** may help you if you search on Algorithm, and Math.
I didn't download the doc to confirm.

 

[GSM Man]

The compiler's Math Library contains all of the math functions it supports. It may, or may not, contain all of the functions listed in the Standard C Math Library, so you have to check it's documentation to see which functions it provides. For details on the Standard C Math Library functions check out this Wikipedia entry:

https://en.wikipedia.org/wiki/C_mathematical_functions

 

[prasad70]

Thank you so much for yours comment.