bjt pnp model
hello, I 'm back! I still have that problem :
Ive got a pnp BJT transistor.. and I wanna plot the characteristic with the Ic at the x axis, and the Vbe at the y axis. so what should I do?
First of all, how would the schematic be? I put an idc source at the collector, something like the following graph attached! but what should I have at emitter and base? (I supposed a common emitter topology). I put a resistor, so that I don't have the same voltage at nodes B and E.have you got any other proposal?
secondly, I have a problem at expressing the Vbe at the output.they told me I should use the calculator but I can't understand how.
what I did is that ; Ι run a dc analysis, design variable, the Ic (at the x axis, the variable i want to sweep)and I choose the Vb as an output cause i don't know how to put the Vbe.
After that, I have to open the calculator, and express the Vbe. in the topology I've done the E voltage is at ground so it is automatically 0V. problem!
Additionally,about the calculator
Ι want to express Vbc for example. I select net of the B, net of the C and put - symbol.
but it can't be plotted!
few questions, ha? any help or suggestion would be useful for me!