i am damaging the breadboard. am i?
i am using a 3 volt battery. the emitter is connected to the positive terminal , does that mean the voltage at the emitter is 3 volts?Consider that there is a PN junction between the base and emitter (effectively it looks like diode) so it has a Vf of around 0.65V. Without resistors you are holding the Arduino outputs to the lower transistors at that voltage and almost certainly overloading the Arduino pins. For the top transistors, consider that to make them conduct you need to raise their base voltage to about 0.65V above their emitters, what voltage is there on the emitters? (hint - what makes the motor operate)
Brian.
I meant the negative terminal of the battery. I meant the positive terminal of the battery.Your transistors have no part numbers.
You make no sense:
1) The positive terminal of what? The motor?
2) The negative terminal of what? The motor?
3) 628 ohms is too high for a little 3V motor.
4) Was the battery disconnected?
A battery has an extremely low internal resistance until it is weak or dead.
The bases of the transistors need a series resistor added so that they or the Arduino are not overloaded and destroyed.
The resistor value is simply calculated from Ohm's Law.
The circuit I showed uses values calculated for a 3A motor and in the circuit with a 12V supply.
"Learning" is not to connect a DVM. And risk the DVM to catch fire.How do I measure the resistance of the battery?
We use cookies and similar technologies for the following purposes:
Do you accept cookies and these technologies?
We use cookies and similar technologies for the following purposes:
Do you accept cookies and these technologies?