Description. Here is the circuit diagram of a very simple wire loop alarm based on a N-channel enhancement FET 2N700, a buzzer and few passive components.In normal condition the gate of 2N700 (Q1) is connected to the ground through a 100K resistor (R2) and the wire loop. When the wire loop is...
my buzzer is at 5-12V I would like to power it 11.1V (box 3x 18650)
can you please advise me which electronic components should i use? (I'm not sure how to calculate it) what components do i need for 11.1V?
I want the batteries to last as long as possible in idle mode.
Those components should be fine for 12V operation.
The wire loop I assume fairly short and just a few ohms max resistance ?
One thing to verify, if you have a oscilloscope, is voltage of MOSFET drain
never exceeds 60 volts when buzzer operating. Or goes negative below ground
for any period of time. Reason for this is you do not know exactly what drive circuit
is like inside the buzzer and its electrical noise generation. And MOSFET has a limit
of Vds of 60V.
If you look at the FET data sheet here you will see VGS(th) is low >0.8V & <3V.
The 4.7M & 100K resistors form a voltage divider and the resulting gate voltage is not low enough to guarantee the fet will turn fully off.
Changing the 100K to a 10K resistor will solve this problem.
If you look at the FET data sheet here you will see VGS(th) is low >0.8V & <3V.
The 4.7M & 100K resistors form a voltage divider and the resulting gate voltage is not low enough to guarantee the fet will turn fully off.
Changing the 100K to a 10K resistor will solve this problem.
What the datasheet says is:
* If V_GS < 0.8V: I_D is certainly less than 1mA
* If V_GS > 3.0V: I_D is certainly greater than 1mA
(under the given conditions)