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Forget the given formula for Fo. That's applicable for a 1st order lowpass only.
I am afraid, it is applicable here too... since R1=R2 and C1=C2... right?
Q for a low-pass filter?
Yes... its inverse gives an indication on how fast the response of a step signal is.
Fo=1/2*3.14*(√R1*R2*C1*C2)
Q=(√R1*R2*C1*C2)/(C2*R1+C2*R2)
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