[SOLVED] Ac Sweep for a single frequency

[ehsantech]

Hello
here is my program and settings
**broken link removed**
**broken link removed**
As you see the simulation settings I want to see voltage output of each nodes @60Hz.but here is my output file information:

**** INCLUDING SCHEMATIC1.net ****
* source PHASORE
R_R1 N00149 N00092 1k
L_L1 N00092 N00096 2mH
C_C1 N00096 0 3uf
V_V1 N00149 0 DC 0Vdc AC 4Vac 10

**** RESUMING wow2.cir ****
.END

**** SMALL SIGNAL BIAS SOLUTION TEMPERATURE = 27.000 DEG C

***************************************************************************
NODE VOLTAGE NODE VOLTAGE NODE VOLTAGE NODE VOLTAGE

(N00092) 0.0000 (N00096) 0.0000 (N00149) 0.0000


VOLTAGE SOURCE CURRENTS
NAME CURRENT

V_V1 0.000E+00

TOTAL POWER DISSIPATION 0.00E+00 WATTS

but I got voltage of each node zero.
what is my mistake?

 

[esp1]

hi,
An AC sweep requires a Start/Finish frequency which are not the same value, also more than one point.

For a fixed frequency use a Time sweep, with V1 set to 60Hz.

E

 

[KlausST]

Hi,

... maybe the voltage readings are DC readings.
Try to use RMS redaings.
Or use a scope.


Klaus

 

[ehsantech]

Thanks for you replay
could you tell me how can see Ac voltage such as Dc voltage on schematic simulation?or how can see the Stady state ac voltage?
Thanks

 

[ehsantech]

Pspice RLC AC analysis

Hello
here is my pspice code and circuit that I want to simulate.

Hello the world
V 1 0 AC 1V
R 1 2 50
L 2 3 .02H
C 3 0 150nf
.ac LIN 4901 100Hz 5kHz
.Probe
.END

as you see the probe windows we have this output(Resistor current and Capacitor voltage)



So we do some calculation
|I|=.02 in resonance frequency (2.9Khz)
|Xc|=1/(2900*150*10^(-9))=2298.8
|Vc|=|I|*|Xc|=.02*2298.8=45.97

but according the V(3)(Capacitor voltage) we have 7.3 at resonance frequency.
other calculation:
we know the Capacitor voltage at resonance frequency is about |VC|=Q*|Vin |

|Vc|=|I|*|Xc|=(|Vin|/R)(1/w0C)=|Vin|*Qc

w0=2900hz
QL=(w0*L)/(R)=1.16
|VC|=Qin*|Vin=1.16*1=1.16

Or

w0=2900hz
QC=(1)/(w0CR)=45.97
|VC|=Qin*|Vin=45.97*1=45.94


If there is no problem could you tell me what are my mistakes?

- - - Updated - - -

Sorry I found my problem
I didn't substitute the resonance frequency into w=2*Pi*F