xman24
Junior Member level 2
Hi..
I am using a divider block in which I dont have a clock. I need to divide the input which s 8 bit, with a value (say 8 ). so that the output of my divider will be divide by value(say 8 (value will be multiples of 2)) output.
I thought of a right shifter (for divide by 8, I will shift right 3 times) , and I implemented a 8 bit Barrell Shifter. But its giving rotate right shift :-(
if my input is 80(8 bit input) then after dividing value say 8 now, then output should be 8 which is a 8 bit value..
Please help.
I am using a divider block in which I dont have a clock. I need to divide the input which s 8 bit, with a value (say 8 ). so that the output of my divider will be divide by value(say 8 (value will be multiples of 2)) output.
I thought of a right shifter (for divide by 8, I will shift right 3 times) , and I implemented a 8 bit Barrell Shifter. But its giving rotate right shift :-(
if my input is 80(8 bit input) then after dividing value say 8 now, then output should be 8 which is a 8 bit value..
Please help.