Swend
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When I have a signal source with a Zs=50Ω output impedance connected to a Zc=50Ω coax cable connected to the Zl=50Ω input impedance of my scope, In this case I understand that the power transferred to the load is 1/2 as per below illustration.
1. Does this Zs=50Ω/Zc=50Ω/Zl=50Ω configuration mean that the voltage signal displayed on the scope is 1/2 of the source output?
2. If I wanted to use this Zs=50Ω/Zc=50Ω/Zl=1MΩ configuration, would I need to terminate with a 50Ω resistor to ground at the load (as seen in the illustration lower right)? Would this be considered 'bridging' so that the displayed signal on the scope is a 1:1 representation of the source output?
3. If I wanted 10x attenuation of the source output signal, could I put a 10MΩ in series with the coax at the load? And should I put a 1.8pF capacitor across the 10MΩ to match the 1MΩ/18pF of the load?
Thank you.
1. Does this Zs=50Ω/Zc=50Ω/Zl=50Ω configuration mean that the voltage signal displayed on the scope is 1/2 of the source output?
2. If I wanted to use this Zs=50Ω/Zc=50Ω/Zl=1MΩ configuration, would I need to terminate with a 50Ω resistor to ground at the load (as seen in the illustration lower right)? Would this be considered 'bridging' so that the displayed signal on the scope is a 1:1 representation of the source output?
3. If I wanted 10x attenuation of the source output signal, could I put a 10MΩ in series with the coax at the load? And should I put a 1.8pF capacitor across the 10MΩ to match the 1MΩ/18pF of the load?
Thank you.