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18th December 2018, 01:32 #21
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Re: Better understanding of capacitor charging
Sorry about that. I wrote it the opposite way. Thanks FvM for pointing that out.
Correction:
The voltage will drop as depicted by formula:
Epsilon*A/d
When you decrease the distance between the plates, the field becomes stronger. This means that the capacitance increases because you now need less energy to keep the charges on the plates as there's already a stronger attraction between the unlike charges on the two plates.
This also implies that the voltage increases since the charges are still intact. This could be easily seen with this known formula:
Q=CV
Since Q is constant, if C decreases, V must increase proportionately. A lower capacitance requires a higher amount of charge to increase the voltage by 1V. Remember?Last edited by Akanimo; 18th December 2018 at 01:40.

Akanimo.
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18th December 2018, 03:36 #22
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Re: Better understanding of capacitor charging
Correction:
The voltage will drop.
When you decrease the distance between the plates, the field becomes stronger. This means that the capacitance increases, as depicted by formula C=Epsilon*A/d, because you now need less energy to keep the charges on the plates as there's already a stronger attraction between the unlike charges on the two plates.
This also implies that the voltage increases since the charges are still intact. This could be easily seen with this known formula:
Q=CV
Since Q is constant, if C decreases, V must increase proportionately. A lower capacitance would have a higher voltage for the same amount of charge difference between the two plates . Remember?Last edited by Akanimo; 18th December 2018 at 03:54.

Akanimo.

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18th December 2018, 07:14 #23
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Re: Better understanding of capacitor charging
As you can see from this link http://hyperphysics.phyastr.gsu.edu...ic/pplate.html , the closer the plates, the higher the capacitance and the lower the voltage. The electrostatic field is stronger when the plates are closer, but it it also shorter.
Ratch
   Updated   
Then you agree that voltage and temperature are energy densities?
RatchHopelessly Pedantic
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