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help soving the intgeral equation

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adnan012

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hi,

the second equation comes after solving the first equation. I need the steps involved. Can anyone help me?
 

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First of all remember that ln(1/x)=-log(x). Second \[\Gamma\] doesn't depends from frequecy then it can be brought out from the integral.
Thus the integral result is simply \[\omega\]b-\[\omega\]a.
This means the equation can be rewritten as:

-ln|gamma|*(wb-wa)=pi/(R0*C1) that means:

ln|gamma|=-pi/[(wb-wa)*(R0*C1)]

that is:

|gamma|=exp{-pi/[(wb-wa)*(R0*C1)]}
 
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