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Question about simulation ICMR (input common mode range)

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chungming

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icmr input common mode range

Hi ~~
If I have a two stage single ended differential amp, and the input is rail to rail (has NMOS & PMOS as input stage), but output is cascode configuration (two nmos cascode & two pmos cascode).
When simulation ICMR we often use unit gain configuration, connect Vin- to Vout so Vin- = Vout, then sweep Vin+.
Vin can rail to rail, but Vout can’t … The ICMR will limit by output swing.
How to simulation real input common mode range ??
Thanks !!
 

Use second amplifier (e.g. ideal voltage controlled voltage source, vcvs) with gain=1. vcvs in+ connect to output of amplifier Vout, in- connect to some fixed voltage e.g. Vdd/2. Connect output of vcvs out+ to Vin-, out- to Vin+. Now you still have unit gain configuration but Vout won't change with ICM voltage and can apply any ICM level as you want.
Note. The output of vcvs will equal to offset voltage.
Good luck
P.S. I've just found you already got this topology "from cadence white paper" in parallel post.
 
Hello. I'm very sorry for bumping this really old thread. But it turns out it has the best explanation I've been able to find regarding icmr testing.
The results using this are great, but I'm afraid I don't fully understand how exactly is it that the output swing is left out of the equation using these.
Could someone please explain this a little bit better?
Thanks to everyone in advance.
Regards,
Ismael
 

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