help with alarm circuit

hello guys
i designed a simple alarm circuit for a pump system we have at our office. this pump system has a signal pin to connect a external alarm (the one im trying to design). This signal behaves in the following way:
*0V when active
*2.62V when inactive

with a LM741, i made a zero-volt comparator to which i connected a led and a buzzer to its output. the idea then, is to compare input with the reference (0v)

after some tests, alarm goes off when signal pin has 0V, opamp has around 10V on its output.
BUT, when input signal has 2.62V (in the case when inactive), the opamp has around 2 volts on its output. this is enough to make the buzzer and led work. the idea is to have 0v on its output when input signal is 2.5v (or different than 0v)

i would appreciate any help give so i can improve my little circuit
thanks!!
moreins

heres is my schematic. "señal" means "signal"
**broken link removed**

the circuit is not correct for operating 741 from a single supply.

better use a comparator for comparing the input voltage to the required value and switch the buzzer on.

hi
its better to use single power supply op amp like lm324,lm358,etc
or use comparatore like lm393,lm311,etc
if u want to cancel that 2volt just add zener diode around 3v with output

u have enough signal to drive base of bjt transistore then use circuit like
this may be help u

hi
its better to use single power supply op amp like lm324,lm358,etc
or use comparatore like lm393,lm311,etc
if u want to cancel that 2volt just add zener diode around 3v with output

u have enough signal to drive base of bjt transistore then use circuit like
this may be help u

hello!
changed the opamp to a 324
worked!!

thanks for al the help!!!