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Sig_A <= Sig_Buse a counter
Check the counter value is X (10) and set sig_a <= sig_b.
if counter = 10 then
siga <= sigb;
end if;this bit of your homework comes for free.
Code:if counter = 10 then siga <= sigb; end if;
ill let you do the rest yourself. come back when you've at least attempted it yourself and are stuck.
process(clk)
variable counter: integer range 0 to 9 :=0;
begin
if rising_edge(clk) then
counter := counter + 1;
if counter = 9 then
Sig_A <= Sig_B;
end if;
end if;
end process;If you want the assignment to happen every 10th clock cycle, you must also add code so the counter wraps back to zero.
An integer variable/signal does not automatically wrap back to the lowest value when you increment from the highest value.
If you want the assignment to happen every 10th clock cycle, you must also add code so the counter wraps back to zero.
An integer variable/signal does not automatically wrap back to the lowest value when you increment from the highest value.
Yeah correct, but this wrap up is not required when the range includes all values (2powerN)
I did figure it out by then actually! Thanks a lot mate! I really appreciate it!
The code I used:
Code:process(clk) variable counter: integer range 0 to 9 :=0; begin if rising_edge(clk) then counter := counter + 1; if counter = 9 then Sig_A <= Sig_B; end if; end if; end process;
