Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.
mrc_ice
hi all
i need the probability density function of SNR after combining from MRC in case of imperfect channel estimation (ICE) in three cases:
1. Rayleigh channel
2. Nakagami channel
3. Ricean channel
please i need just paper talk about this point
regrads
simple but urgent
hi all
i have small question that i don't understand
what is the different between the pdf (probability density function) and channel model it self ?
in other word if i have 'h' (channel model like Rayleigh) how to find the pdf ?
i know the pdf of Rayleigh, but the...
urgent_MRC
hi all,
i need paper or book to find probability density function (pdf) for ricean channel in MRC diversity in :
1. i.i.d
2. i.n.d
thanks for all
please
i need paper or equation to find total probability of all branches in Rayleigh channel with i.n.d in MRC
since the total SNR is summation for all branches , what about total BER ?
thanks
Added after 30 minutes:
thanks for all,
i found paper talk in all cases
MRC expert
so in i.n.d ?
do you have paper for this case ?
Added after 2 minutes:
daer insatiable
equation 7.20 for i.id case,
i need for i.n.d ?
Added after 1 hours 13 minutes:
Added after 3 hours 14 minutes:
please
i need paper or equation to find total probability of all...
MRC expert
hi all,,
for non identical branch, there are snr for each branch so total snr is summation for all snr in each branch.
what about BER, is it all summation for all BER in each branch, or it is the mean of all branch, or min. BER or what?
i hope to tel me ASAP
thanks
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.