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What is the Unit of Moment of Inertia in the Torque Equation T = Mi X Acceleration?
and what will be the Unit of resulting torque value?
for example.if the Mi = 33Nm^2 ( 3.37 Kg.meter^2) and the Acceleration is 17.46 rads/sec^2..
the SI unit of Mi is kg.m^2
what value is used for Mi , Nm^2...
so by taking the calculations you made and the theorem you said "Any minimum torque τ is enough to accelerate any Moment of Inertia (MI) with an angular acceleration α"
i think i need not worry about how much torque is necessary to just start the rotation of the shaft..
rather i need to...
yes,thank you that makes sense...
the torque after overcoming the bearing friction,will accelarate the mass,if the torque is more,then it accelerates the shaft quicker,if the torque is low,the acceleration is slow..i understood it clearly..
but my confusion is, how do i know how much torque...
thank you all for helping me understand this thing , my assumption on torque was wrong so far..
ill revisit the static friction part later,that is a hard one i guess so
so i will assume that,there is no friction in the rotor(hypothetically),
and now the shaft has 33 Newtons of Moment of...
So u mean that the 12v dc motor can rotate the 1kg metal plate wen it the shaft is connected to the CG but the angular velocity will be very low ? Did i get that right ??
So this 12v motor cannot say produce enough torque to rotate the metal plate at say 100rads /sec because the dry friction...
Thank u god n chow,i understood wat u explained n i agree with it,but my confusion is there will be some intertia,as the weight of the blades sum up to 4.5 kg,so the motor has to apply some amount of torque to put a rotating force more than the intertia of the shaft to over come the inertia n...
Simple question about on how much Torque is necessary by a DC motor to rotate a rotor arrangement..
This image below sums up my question more clear,its a hypothetical setup i know,but its just for my understanding
the length of each blade being 1.5 meter
As you can see,there's a electric...
Re: Serial port programming in Visual Studio >Visual Basic> Windows form application
use the Serial class communicate through serial port with the device
Serial.getPortNames() -- gets you the port available on windows
Serial.baudrate() to set baud rate,and partiy,timeout and other stuff,set...
Well,as far as i know,the Engine with 6.5HP and 11Nm torque connected to that 3 Kg of blades will not be able to start the engine,so the blades need to be rotated manually or engine should be cranked manually,until the piston reaches a certain RPM from where the engine can run on its own...
@Barry
Well,i agree with what you said,i am new to the field of mechanics,well,it would be tough for some one from the field of coding and logic to real world Mechanical physics,at-least for me....
Well,my question might be kind of wrong in my #1 post,now i just a simple question to understand...
i am little confused about Torque which is measured in Newton meter...
Aussume,i have a engine which produces a 11Nm of torque at 2500RPM
the shaft of the engine is connected to a steel pipe which weighs 1kg..
so as far as i know,11Nm of torqe is the capacity of engine to turn something which...
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