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Since X3 is s-a-1 we will give it 0 and we will give x2 = 1/0. Now if x2=1/0 and x3=0 so c1=1(verified whether c1 is s-a-0)
to drive c2 to 1 we need to give x4 = 0 and c1 is 1 from the above case.
so (x1,x2,x3,x4) = (*,1/0,0,0)
My bad I assumed them as Nand gate. In the above case we will require 2 sets of inputs. Work out you will get it. Add an XOR gate it creates some complications.
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