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The same way as you would measure the internal resistance of a battery ..
Measure the voltage with no load (or minimum required load) then measure the voltage with rated load ..
The internal resistance can be estimated by using the following formula:
Rint=(Vnoload-Vload)/Iload
Understand, however, i re modified the equation and become E = I (R+r).
where E = Voltage without load; I= current with load; R = load; r = internal resistance. Right?
However, in practicing, the value of I*R > value E, is this valid?
I'm using 27 ohm as load, the E = 4.974 V (measurement by voltmeter), R = 27.24 (after take 5 times measurement); and the I = 0.1904 A (measurement by ammeter). By this info, after calculate, the internal resistance, r = -1.1245 ohm.
So, i wish to ask , E must more than I*R? Or there's is other ways to get the internal resistance of power supply?
Added after 8 minutes:
For Info. One of the ways to get internal resistance; by the way, there are no description about how to measure the power supply internal resistance.
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