how to do bit shift in __int64??

[boeysue]

bitwise shift __int64

__int64 i=0;

i>>=9;

why i is not 0??

and how to do in the right shift??

 

[chewbecca]

__int64 to zero

divide it by 2

 

[echo47]

__int64 shift

Is this C? That __int64 sounds like a language extension provided by your compiler. If it is a 64 bit integer type, then your right-shift should work fine. Maybe the way you tested i is incorrect. Tell us which compiler you are using, and show us a small complete program that demonstrates the problem, and maybe we can help you find the trouble.

For example, MinGW (gcc 3.4.2) provides __int64, and this correctly prints "i is zero":

#include <stdio.h>

int main(void)
{
  __int64 i=0;

  i >>= 9;
  if (i == 0)
    printf("i is zero\n");
  else
    printf("i is not zero\n");
  return 0;
}

 

[raj_rohit10]

hi,
I have also checked on sun compiler it is working perfectly fine,....

 

[mozes]

hi all
also working fine with MinGW 2.05(under winxp)