yokahu
Newbie level 6
Hi guys,
I have a doubt regarding the efficiency calculations for an inverter (DC-AC). I know that to calculate efficiency i have to divide power-out/power-in and power is i^2*R, V^2/R, etc, but there is something troubling me about the calculations when there is an RMS value. How do I calculate the efficiency of a FullBridge inverter when the input is dc and the output is rms?
Po=Vrms*Irms ? Or is it something like Vpk-pk*Irms?
Let’s say we have an ideal Full Bridge Inverter with an input of 169.7Vdc, with a resistive load, and I want an output of 120Vrms, 1kW. Does that mean that the output current must be 8.3Amps-RMS (8.3*120=1k)? If the inverter is 100% efficient, the input current has to be 1000/169.7=5.9Adc, but 5.9/sqrt(2)=4.17Arms and not 8.3Arms.
Thanks
I have a doubt regarding the efficiency calculations for an inverter (DC-AC). I know that to calculate efficiency i have to divide power-out/power-in and power is i^2*R, V^2/R, etc, but there is something troubling me about the calculations when there is an RMS value. How do I calculate the efficiency of a FullBridge inverter when the input is dc and the output is rms?
Po=Vrms*Irms ? Or is it something like Vpk-pk*Irms?
Let’s say we have an ideal Full Bridge Inverter with an input of 169.7Vdc, with a resistive load, and I want an output of 120Vrms, 1kW. Does that mean that the output current must be 8.3Amps-RMS (8.3*120=1k)? If the inverter is 100% efficient, the input current has to be 1000/169.7=5.9Adc, but 5.9/sqrt(2)=4.17Arms and not 8.3Arms.
Thanks