About Torque in DC gear motor.

[sysysy]

Hi all,

i am doing a mobile robot project. I am using 2 dc gear motor to control my car movement. May i know what will be the maximum load of my robot to make sure my robot can run smoothly.

For example,
The at load information given by motor datasheet is,

current: 0.5A speed(RPM):112 then the Torque 2.16Kg.cm

for what i know is, if my radius of my wheel is 1cm, then the load muz be lower then 2.16kg. but now i using 2 dc motor, 1 as a right wheel and 1 as a left wheel.

so in this situation, may i know more accurate or precise way to calculate how weight my robot can carry. (* Basically my robot load just including wheel, robot chassis, breadboard circuit, variety of component)

Instead of implement experiment, i hope i can know some correct design method for my robot carry weight.

hope can get some knowledge from u guys.

Thanks.


Regards,

sysysy

 

[kabiru]

In all conditions the total weight of the robot must be less than motor torgue,dont forget W=mg.

 

[FvM]

In all conditions the total weight of the robot must be less than motor torgue,dont forget W=mg

Yes, if the robot is intended to drive in a vertical direction, in other words operate as an elevator. Otherwise a factor sin(φ) for the pitch angle applies.

 

[Rocketmagnet]

Yes, if the robot is intended to drive in a vertical direction, in other words operate as an elevator. Otherwise a factor sin(φ) for the pitch angle applies.

Plus the rolling resistance, which is a linear function of the weight of the robot. If the robot is driving on a flat surface, then this will be the only factor.

You can measure the rolling resistance by disconnecting the motor, and putting the robot on an angled surface.

The rolling resistance - mass of robot x 9.8 x sin(min angle required to cause robot to roll)

Hugo