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4-bit BCD Adder (Calculator Style)

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The maximum count = 9+9 = 18 => 12 (hex)

Even for the hex to 7 segments decoder still need to use the two digits display.
 

How can you place 9 + 9 in that circuit?

---------- Post added at 22:31 ---------- Previous post was at 22:09 ----------

How can you place 9 + 9 in that circuit?
 

That's simple if we set A = 1001 and also set B = 1001...
 

What if I just want to design a calculator style where it displays it real value, say if 10 is the output, instead of displaying the equivalent which is A, the display would output it's real value of 10? How can that be done? Thanks.
 

Update: We only need one 7 segment display
 

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