Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

A question on one of Lee's paper on LNA

Status
Not open for further replies.

Ruritania

Member level 5
Joined
Nov 18, 2004
Messages
93
Helped
4
Reputation
8
Reaction score
3
Trophy points
1,288
Activity points
856
Hi,

I have a question on one of the most often cited papers of Thomas H. Lee's: "A 1.5-V, 1.5-GHz CMOS Low Noise Amplifier" (IEEE JSSC, Vol.32, No.5, 1997)

Where does the denominator (1+ωT*Ls/Rs)² come from in the equation (12)?? Isn't that the channel resistance noise (id) itself is located at the output, and contributes itself totally to the output noise power?

Thanks.

Ruri
 

Split id to two identical noise sources, one is inserted between output and ground, the other is inserted between source node and ground. Calculate the total output noise current while the output node is shorted to ground.

Then, you'll get the exact equation above. Don't forget to ignore rds :)

Why the output noise current is not id? It is because that id is injected to the source node, this cause the source node votage to rise, then rise the Vgs in negative direction and so does gmVgs. The total output noise is (gmVgs + id). If Ls = 0, then the injected noise current to source node does not affect the source node voltage. Under this situation, the total output noise current is id.
 

    Ruritania

    Points: 2
    Helpful Answer Positive Rating
Status
Not open for further replies.

Similar threads

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top