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but I think inductance value is : Leq=Cgs2/(gm1*gm2)
and active inductor converts parasitic capacitance of transistor to inductance and no need to add external C here
Hi bicave
I'm simulating active inductor, but I am newbie too , why you put capacitor between drain and source? are the transistors in saturation region?
at first thanks in advance for your quick and good helps
This indicates that the series losses are dominant because -|Rq| acts as a series resistor.
-|Rq| acts as series with which element that has effect on Q?
is you mean -|Rq| series with Rseries ( as you named ) in equivalent passive...
It will not be surprising if the series loss resistance is smaller than the parallel loss resistance. However, this does not mean that the parallel losses dominate. In contrary - a large parallel resistor (like a small series resistor) causes comparable small losses.
yes I know for increase Q...
No, it is not. Some information of the VALUES are interesting - for example, to know if the series or the parallel losses are dominant. This is necessary for explaining the effect of Q increase (as desired by you).
series is gds1/(gm1gm2) and parallel is 1/gm1 it seems that series has...
my question is, if you are able to derive from the active circuit behaviour some information on the equivalent circuit? For example, what is the desired L value at what frequency? Are series or parallel losses dominant?
at #1 in the first picture you can see the equivalent circuit elements...
Question: From your measurements/simulations do you have some parts values for the equivalent circuit?
I simulate the active circuit no the equivalent passive circuit.
Second question (for clarification): What is R1 in your first posting? Is it a lumped element (resistor) that is actually...
I think you mean is :
now 2 question:
1-why the -Rn (cross-coupled) between source of M2 and gate of M1 placed in parallel with Rloss in the passive element model of the basic circuit(2mosfet and 2 current source) ?
2-when I put cross-coupled pair between source of M2 and gate of M1 I need...
let me ask my question in another form
the cross-coupled pair has negative resistance, yes it is true, but when it is in parallel with a resistor that the value of it is positive and smaller than the magnitude of Real{Zcross-coupled}, then the Their equivalent circuit has not negative...
Hi zorro,
thanks for your reply
Is you mean that just the role of r2 is increasing r1? on the other hand can I delet the pair and increasing r1 value instead of it?
Is you mean from parallel RL or RC the equal circuit can be replaced instead of r1 and its parallel pair?
if the answer is yes...
Hi zorro
yes the pair has negative resistance and its value is more than R1,
could you please describe me more? what do you mean "Such an element increase Q because it increases parallel resistance" ?
Hello
the below picture show an activer inductor basic circuit (figure "a" ) and its equal small signal model (figure "b" ), and the Q factor is defined Real(Zin)/Image(Zin)
the below procedure can increase the value of Q-factor, Is it possible describe to me that how this procedure can...
Thanks in advance LvW and pancho_hideboo, I read your conversation and I learn many things, at first I had confused beacuse I mixed up definition of Q but now I learn that the Q-factor of active inductor circuit(black box) can be calculated as Image(Zin)/Real(Zin), that this Q at resonance...
at first I should say beacuse of my english language isnt very good maybe I cant understand some parts of your sentences or maybe understand wrong.
if I ask your idea the reason is that I am newbie in designing and I think you are more skilled.
my final goal is designing an active inductor with...
@pancho_hideboo: my problem is for this circuit(active inductor) that should I use resonator Q or inductor Q!!!?
@LvW: whats your idea? for this circuit(basic gyrator-C active inductor) which Q is important and which of them I should calculate and simulate?
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