Hi,
thanks for your reply. i knew the time and frequency response can be calculated using exponential function and laplace transform respectively. however, calculating time response is more complicated as it involves exponential. don't you think the method stated in the first post is relatively quick and intuitive?
Laktronics,
no, the step input is 0 at 0ns and 1 thereafter. pumping this to a high pass filter would have a response of a peak and exponential decay. while in the first post the method can give the decaying voltage output at any instance after the step. i am wondering how it can be done this way?
thanks
best regards
gd