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Why DDR termination voltage is half the supply voltage

hioyo

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May I know why DDR termination voltage is kept half of the supply voltage.
 
Does it have any relation to the power dissipation in the termination resistor.Below statement is taken from an
application note.
"
the
termination resistor is connected to a supply voltage
(VTT) that is one-half the VDD voltage. The dissipation in
the termination resistor is then constant regardless of the
supply voltage and is equal to VTT [or (VDD/2)] squared
divided by the termination resistance.
"
--- Updated ---

"because that’s the middle of range of the signal voltage swing." May I know what is the advantage of this
 
Last edited:
May I know why DDR termination voltage is kept half of the supply voltage.
Using a termination voltage that is half the supply voltage is an important design choice for DDR memory that helps ensure signal integrity and minimize power consumption.
 

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