[SOLVED] Why do we need to use Vdd in a current mirror ?

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alikemal

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Hi
I am new about current mirrors and i dont understand why we need to use Vdd ? because we already use a current source.
 

So if i dont use Vdd in a simulation, what will happen?
 

If you assume that the current source has an internal energy source (an ideal current source in a simulation of course has), you don't need Vdd. A technical current source, e.g. a transistor circuit will need an external energy source.

- - - Updated - - -

No difference at all.
 
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