Does it have any relation to the power dissipation in the termination resistor.Below statement is taken from an
application note.
"
the
termination resistor is connected to a supply voltage
(VTT) that is one-half the VDD voltage. The dissipation in
the termination resistor is then constant regardless of the
supply voltage and is equal to VTT [or (VDD/2)] squared
divided by the termination resistance.
"
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"because that’s the middle of range of the signal voltage swing." May I know what is the advantage of this
Using a termination voltage that is half the supply voltage is an important design choice for DDR memory that helps ensure signal integrity and minimize power consumption.