Can someone tell me why the current through an inductor rises linearly when a constant voltage is applied across an inductor. Please don't explain in terms of equations because I know V = L * dI/dt and so I is the integral of voltage applied over time and therefore I = ( V * t ) / L. I would appreciate if someone can tell me the exact mechanism, in terms of the magnetic flux/field, self-induced voltage etc.
No one can. You would do well to look at the equation for current through an inductor when a constant voltage is applied. It is I = (E/R)(1-exp(-t/(L/R))). As you can see, current through a inductor has an exponential relationship, not a linear one.
from experience i learnt to become a better person not to just read the heading
and really true i did not go through the heading of the post fully
your explanation is correct as i find the fact is in general all memory devices behave linearly in constant supply voltage
memory devices uses the rate of variations produced (frequency) of the signal input and respond diversely and show their corresponding characteristic curve
if the rate of change of ip is 0 (as in the case of constant sources) they behave linearly (inductor) or as an open circuit (capacitor) as there is no point where these devices can discharge their memories (voltage or current) to the external circuit
memory devices uses the rate of variations produced (frequency) of the signal input and respond diversely and show their corresponding characteristic curve