Surianova said:
in negative feedback, the transfer function is
H(s)= G/ (1+GH) , G=open loop gain, H=feedback gain
vout= G/ (1+GH) * vin
divide by G
vout= 1/ [1/G + H] * vin
When G is high , vout almost equal to vout=1/H
for example, test for 2 case
1. vin=1.2, G= 100,assume H=1 for buffer
vout= 1/ [1/G + H] * vin
what is vout ?
2. vin=1.2 , G=1000
what is vout?
From this 2 case, when the gain is high, the vout is more closer to 1.2 input
Hope this will help.