exp(j*psi) = exp(j*2*pi*100) * exp(j*2*pi*t*(200+500*t))
First multiplier is constant and it is related to amplitude of signal together with 7.7
Second is chirp wave. Argument 2*pi*f*t = 2*pi*t*(200+500*t))
So f = 200 + 500*t
So min is 200 and max is 500*dur.
thank you zorro and thank you Mityan but how can i substitute the maximum f value in the script written above and to verify about minimum frequency.
regards