Even in your answer somethings are in contrast you said 0.125 Vp = 0.25Vpp on the other hand 2Vpp=2Vp
Actualy I found the answer and that is 0.5Vppd corresponds to an amplitude of a 0.25 for a sine wave that means Vppd = Vpp when you model a differential input with a single input.
Thanks for your messages
Mahyar
Even in your answer somethings are in contrast you said 0.125 Vp = 0.25Vpp on the other hand 2Vpp=2Vp
Actualy I found the answer and that is 0.5Vppd corresponds to an amplitude of a 0.25 for a sine wave that means Vppd = Vpp when you model a differential input with a single input.
Thanks for your messages
Mahyar