You can replace the diode with a 10 ohm resistor and a 0.7 volt power supply. Then a equation should be solved to find the Voltage across the diode which is:
(-690) / 998 = -0.69138276553
You can replace the diode with a 10 ohm resistor and a 0.7 volt power supply. Then a equation should be solved to find the Voltage across the diode which is:
(-690) / 998 = -0.69138276553
Two rough assumptions (without explanation) - and a result with a pico-volts accuracy.´?
No - without any further information, we have no other chance than to ASSUME 0.7V across the diode and find the current through the diode (method of node voltages): Id=0.86mA.
You can calculate the Thevenin equivalent of the circuit without the diode.
From that you can calculate the current through the diode when it is connected.
No - without any further information, we have no other chance than to ASSUME 0.7V across the diode and find the current through the diode (method of node voltages): Id=0.86mA.
Yes. The OP is apparently assuming 0.7V with 10 ohm series resistance as model, without stating this explicitly or even a substantiation. In this case, the exact current would be
4.3 V/5.01 kOhm = 0.858 mA, negligible difference to the simplified calculation without series resistance. Post #5 is wrong in any case.