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the bw of square pulse is =1/T where T is the high time of pulse (if base band)
if pass band signal multiply by 2
if raised cosine is used bw = Rb/2*(1+α) where α is the roll off factor of filter
sure 1/T = Rb
& second case is geneal case
if ideal nyquist channel is assumed therefore bw =Rb/2
yes, the bandwidth of a square pulse is infinity.
but there is no practical base band digital communication to transmit square pulse. it is always passband. normally we use a raised cosine which is like a sinc with few side bands, in the time domain.
ok i know that bandwidth of pulse os infinity...let me convince u by what im saying..lets draw the pulse in the frequency domain..let the pulse width in time is T therfore the pulse in frequency is equal to sinc with first null equal to 1/T &extends to infinity..& since most of power exists in the main lobe( fisrt null to null) therefore we can assume that the bandwidth of the pulse is equal to 1/T ..u can review haykin for this..&by the way im a student in faculty of engineering &we took this method this year,,...i didn't invent it..