what does this operator stands for ^=

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RubyS

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I was reading some paper regarding galios field and a snippet of code was given as shown below

for i = 0:7
for j = 0:7
result [i+j] ^= a[j] & b

in this i m not able to understand the operator "^=".Is this some reduction operator..kindly help
 

In BASIC there is a shorthand expression that goes:

result += a

In longhand it means:

result = result + a

There's a chance your code uses a similar type of shorthand.

The '^' operator normally means 'raise to the power of'.
 

RubyS said:
I was reading some paper regarding galios field and a snippet of code was given as shown below
Click to expand...

Code of which language?

I haven't seen for i = 0:7 in C but maybe the XOR operator is the same.
 

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