two-port exercise question

[johnis32]

Hi,
I found an old exercise in which you had a voltage source connected in series with an resistor and then with the two-port. The second side of the two-port is connected with a resistor. The two-port is linear and passive. The problem is that the voltage source is 4V and the exercise tells you that the voltage of the second resistor is 6V. Can this happen without active components?
Thank you in advance.

 

[ahmad1954]

probably the two ports network has dependent source.

 

[johnis32]

Yes, that's what i though but the exercise says that the two ports is passive and linear. I am guessing that this exercise is wrong and the 6V is only to make the calculation easier.