@cmancuso I think you've misunderstood the OP's question, but there's been a lot of confusion on this thread.
It would help if the OP gave us one single circuit, rather than the two circuits and asking us to imagine how one of his circuits (the switch) turns the other circuit (the oscillator) on and off.
@hayowazzup
My own understanding of your question is, YES, the switch WILL turn the oscillator on and off.
But its a very poor way of doing it! Apart from the poor current paths and the DC thump when switching the oscillator on and off, it is quite unnecessary to do it this way.
If you concentrate on the oscillator circuit and ask the simple question: what is the most effective method of turning this oscillator on or off?, then I think you'll find better solutions.
If your switch is local and mechanical, you could simply disconnect one end of the crystal or break the circuit's output connection.
If your switch is remote and/or electronic, then I'd advise using your 'switch circuit' so that the collector | emitter terminals of the 'switch' are connected across the crystal (so that the 'switch' either lets it operate as an oscillator or shorts it causing it to stop oscillating.
(You could also consider letting the oscillator run continuously, and apply the 'switch' circuit to its output. This could clamp the output to ground when you want to switch the oscillator's output 'off', and leave the output unnaffected when you want the oscillator to be 'on'.
Hope this helps