Hi jimeece13,
may I try to answer your questions?
g1-C1 is the first integrator that corresponds to opamp1,R1,C1 to my schematic that i uploaded above.Where is the resistance R3 to the equivalent circuit with the OTAs?
No, g1-C1 mimics the second integrator. Both integrating stages are interchanged.
This is no problem for series connections.Therefore, no equivalent for R3.
What is the role of g3?Does it play the role of the inverting unity gain configuration of opamp3,R5,R6 (R5=R6) of my picture?
No, the inverter is not required since it is easy to implement a non-inv. integrator in OTA technique. This has been done with the second stage.
The role of g3 is to provide damping of the second integrator (role of R3 in the opamp realization). Such an OTA configuration always can be used to simulate a grounded resistor.
Which is the role of the feedback connection from v02 to inverting input of the first OTA in the schematic you uploaded?And finally where is the R2 from my pic to the pic you uploaded?
Such a feedback, of course, is always necessary for an active filter with pole Qs higher than 0.5. The same applies to the opamp configuration.
The resistor R2 was necessary for combining two voltages at the inverting opamp terminal. This is not the case in the OTA structure since the input is at the pos. terminal. More than that, watch the additional inputs which are available only in OTA technique.
Perhaps this helps.
Regards