Resistance of a conductor is directly proparational to its length and inversely propartional to its thickness or area.
As you know resistance is inversely proparational to current as per Ohms law.
This is what you required?
Regards,
Satya
consider a case where in there is a wire of width 64µm and four wires of width 16µm stacked one above the other...... can anyone just tel me what would be the relationship between the two cases in terms of resistance.....
The resistance is inversely proportional to the thickness(cross sectional area) of the wire......
WHen u double the cross section area,the resistanca bcomes 1\2 of the original.......
Added after 1 minutes:
phy_des said:
consider a case where in there is a wire of width 64µm and four wires of width 16µm stacked one above the other...... can anyone just tel me what would be the relationship between the two cases in terms of resistance.....
(circular wire)(16um and 64 um length same here lengths of 5 wires r same)
in 16µm case ..the resisstace is R=(ρl/πr²)
and u r saying that those wires in parallel then the
resistance R/4.
in 64µm case.then the resistance is (ρl/πr²(4²)) i.e R/16
THEN RI6=4*R64...
if we take two wire of same length the resistance same....