while surfing i found such a question...
i couldn find the answer...
could you help me...
You go to the lab, and connect a battery across the terminals of a black box. Then, using the instruments on the bench, you measure the following:
Voltage across the terminals: 1 V.
Current entering the box: 2 A.
Power dissipation of the box (measured by a watt meter): 0 W.
What is in the box?
The box could contain a 1 volt battery in series with a 0.5 ohm resistor. If you measure the voltage with a high impedance voltmeter, no current will flow and you will measure the battery voltage of 1 volt. If you measure the current with a zero resistance ammeter, then the current will follow Ohm's law (1 volt/0.5 ohm) and will be 2 amperes. If you measure the power dissipation of the box, it will be zero since no current wil flow if no load is connected to the box's terminals; 0 watts are dissipated.