[SOLVED] system verilog squareroot with out rounding....

Status
Not open for further replies.
D

dipin

Full Member level 4
Joined
Jul 16, 2014
Messages
223
Helped
14
Reputation
28
Reaction score
14
Trophy points
18
Activity points
1,731
hi,

in system verilog , to find the square root $sqrt(x) function can be used . but it is rounding the values.

example if the input value is 95 then $sqrt(x) will give root as 10.
is there any way to get it as 9??????

i have tried t**0.5 also. but it too rounding the value.:???:

i am new in system verilog. if you know please help.


thanks & regards
 

$sqrt() doesn't perform any rounding, it takes place because you assign the result to integer variable.

To get the intended result, learn about $floor() and $ceil(). You should also get a basic understanding of numeric types and automatic type conversions in SV to solve similar problems yourself.
 
Reactions: dipin

    D

    dipin

    Points: 2
    Helpful Answer Positive Rating
hi,

thanks fvm . i used $floor()

regards
 

Status
Not open for further replies.

Similar threads

Menu
Log in
Register
Cookies are required to use this site. You must accept them to continue using the site. Learn more…