I have a following voltage doubler design (Fig.1) with the appropriate DC Voltage of 3V at 10 dBm as shown in Fig.2
I wanted your suggestions in following:
1. I want to have a DC Voltage of about 1-3 V at the input power level of [-60 dBm to -40 dBm]. How can I acheive that? Should I increase and play with the values of lumped elements or should I add more diodes into the circuit?
You can see from your graphs that the diodes do not produce any voltage output with an input of less then -30 dBm. So you must amplify your signal to get it to at least this figure. Adding more diode (?) will not help.
Frank
Now depends by your load resistance.
-60dBm (0.000000001W) it is a very low power, and to produce +3V after the detector (any type) it is practically impossible.
@Chuckey and @vfone: Thankyou for the quick response.
I guess amplifier is an optimal solution. Kindly let me know which amplifiers to use and at which stage in the circuit it should be introduced.