STM32 Debug - Print GPIOA register value

[metRo_]

HI,
I'm trying to print the GPIOA->BSRR register value but with no success :s

(gdb) n
67              GPIOC->BSRR = GPIO_Pin_9;
(gdb) p/x *(0x40010800 + 0x10)
$6 = 0x0
(gdb) n
 
Breakpoint 1, main () at main.c:68
68              GPIOC->BRR = GPIO_Pin_9;
(gdb) p/x *(0x40010800 + 0x10)
$7 = 0x0
(gdb)

The pin is well configured cause the led in the board change the state. Do you have any idea how can I do that?

 

[Jinzpaul4u]

Hello

I'm trying to print the GPIOA->BSRR register value but with no success :s

GPIOC->BSRR = GPIO_Pin_9;

??

GPIOC->BRR = GPIO_Pin_9;

I am confused! is it GPIOA or GPIOC??

update me,

Best regards,

 

[metRo_]

Hello



??




I am confused! is it GPIOA or GPIOC??

update me,

Best regards,

I mean GPIOC and I used the map address for GPIOA but now with the correct memory address it still not working:

(gdb) n
65              GPIOC->BSRR = GPIO_Pin_9;
(gdb) p/x *(0x40011000+0x10)
$7 = 0x0
(gdb) n
66              GPIOC->BRR = GPIO_Pin_9;
(gdb) p/x *(0x40011000+0x10)
$8 = 0x0
(gdb) n
67              GPIOC->BSRR = GPIO_Pin_9;
(gdb) p/x *(0x40011000+0x10)
$9 = 0x0
(gdb)

but if I try with the IDR register it works:

(gdb) n
66              GPIOC->BRR = GPIO_Pin_9;
(gdb) p/t *(0x40011000+0x08)
$15 = 1111101111111111
(gdb) n
67              GPIOC->BSRR = GPIO_Pin_9;
(gdb) p/t *(0x40011000+0x08)
$16 = 1111100111111111
(gdb) n
68              GPIOC->BRR = GPIO_Pin_9;
(gdb) p/t *(0x40011000+0x08)
$17 = 1111101111111111
(gdb)