Simplify Boolean Function

[littlechicken]

Hi! Everyone,
Pls help me simplify these Boolean Function:
1. VW + VWX'Y + VWYZ' + VWX'Z + X'YZ
2. ABC + B'D'E' + ADF + ACD'E' + AF
Thanks

 

[2339]

VW( 1+x'y+yz'+x'z)+x'yz

vw+x'yz
--------------------------------------------



ABC + B'D'E' + ADF + ACD'E' + AF
ABC + AF(D+1) +B'D'E' + ACD'E'
ABC+AF+B'D'E' + ACD'E'
AC(B+D'E')+AF+B'D'E'
D'E'(AC+B')+ACB+AF
AC(D'E'+B)+D'E'+AF
D'E'(AC+1)+ACB+AF
D'E'+ACB+AF

any question else iam ready

Ahmed

 

[xt880731]

VW( 1+x'y+yz'+x'z)+x'yz

vw+x'yz
--------------------------------------------



ABC + B'D'E' + ADF + ACD'E' + AF
ABC + AF(D+1) +B'D'E' + ACD'E'
ABC+AF+B'D'E' + ACD'E'
AC(B+D'E')+AF+B'D'E'
D'E'(AC+B')+ACB+AF
AC(D'E'+B)+D'E'+AF
D'E'(AC+1)+ACB+AF
D'E'+ACB+AF

any question else iam ready

Ahmed

HI i dont know how to change D'E'(AC+B')+ACB+AF to AC(D'E'+B)+D'E'+AF thank you

 

[_Eduardo_]

Sure?

ABC + B'D'E' + ADF + ACD'E' + AF
.......................................
D'E'+ACB+AF

When A=0 ==> Out = B'D'E' <> D'E'

 

[xt880731]

Sure?



When A=0 ==> Out = B'D'E' <> D'E'

HI thank you, but i still dont understand why B'D'E'= D'E'?

 

[_Eduardo_]

What I want to say was that the procedure had an error.


ABC + B'D'E' + ADF + ACD'E' + AF
ABC + AF(D+1) +B'D'E' + ACD'E'
ABC+AF+B'D'E' + ACD'E'
AC(B+D'E')+AF+B'D'E'
D'E'(AC+B')+ACB+AF
AC(D'E'+B)+D'E'+AF <-- wrong, is AC(D'E'+B)+B'D'E'+AF