rudie
Junior Member level 3
Hello guys,
I want to protect my circuit against a wrong conneted power supply (changed polarity). To do this i want to use a diode. If I use the S1A for fairchild semicondutor. The maximum voltage at 1A is 1.1V. The maximum power dissipation is 1.4W. In my appilication the current that is needed is 0,4A. So the maximum voltage with this current would be:
P=I^2*R -> R=P/I^2 -> R=1.4W/0.4^2=8.75ohm
P=V^2/R -> V^2=P*R=1.4W*8.75ohm=12.25 -> V=3.5V
is this correct??
Greets Rudie
I want to protect my circuit against a wrong conneted power supply (changed polarity). To do this i want to use a diode. If I use the S1A for fairchild semicondutor. The maximum voltage at 1A is 1.1V. The maximum power dissipation is 1.4W. In my appilication the current that is needed is 0,4A. So the maximum voltage with this current would be:
P=I^2*R -> R=P/I^2 -> R=1.4W/0.4^2=8.75ohm
P=V^2/R -> V^2=P*R=1.4W*8.75ohm=12.25 -> V=3.5V
is this correct??
Greets Rudie