Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

Simple circuit board problem

Status
Not open for further replies.
You should do your homeworks by yourself.
However, as an hint, consider just one generator at a time (while the other is shorted) and calculate the voltage between the two nodes you want then apply the superposition. This means you will have Vab(1) with the 14V working and the 30V shorted and Vab(2) with the 30V working and the 14V shorted so Vab=Vab(1)+Vab(2). The same to calculate Vbc.
 

I would simply calculate the current in the loop, 1A (30V-14V and 16 ohms of resistance). The circuit is not complicated enough to need anything more. From the current, the voltage drops can be calculated.

Keith
 

Status
Not open for further replies.

Similar threads

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top