RF power amplifier efficiency in keysight ADS

[oumik]

Is the below equation valid to calculate RF power amplifier efficiency?

Probe4 is placed right before a resistor where DC voltage component of the amplified RF OUT power is supposed to be measured and Probe2 measures RF power IN.

 

[BigBoss]

Why you consider ALL harmonics' Power ?? Would you interested in the first harmonic only ?

 

[oumik]

Why you consider ALL harmonics' Power ?? Would you interested in the first harmonic only ?

Yes only the first harmonic P_Probe2.p[1]. But is there a formula for calculating efficiency of the DC output power to RF input power?

 

[BigBoss]

DC output Power ?? Simple...
P_Probe.p[0}


"Zero" represents always DC component of HB analysis.

Efficiency=(P_probe_Output.p[0]-P_probe_Input[.p1])/P_probe_DC.p[0]

If I understood your case.

 

[oumik]

DC output Power ?? Simple...
P_Probe.p[0}


"Zero" represents always DC component of HB analysis.

Efficiency=(P_probe_Output.p[0]-P_probe_Input[.p1])/P_probe_DC.p[0]

If I understood your case.

Thank you for your answer. Is this equation valid though? Can I just replace the RF output with DC?

 

[BigBoss]

If there is a DC component at RF_Out Port, you can measure it.
If you draw your test set-up, I can say something more concrete. I don't wanna guide you incorrectly.