Resistor in HFSS for a Wilkinson power divider

[belma1511]

Hello,

currently I'm trying to simulate a 100Ω thin resistor for a Wilkinson power divider.
Could anyone explain me in detail how to do it,especially how to determine the current line?

Thanks in advance

 

[psuclint]

I'm not sure exactly what you're doing, but I can explain how to use a lumped RLC boundary in HFSS and set its resistance to 100Ω. Regarding the current line (for a lumped RLC boundary), you just set the starting point at one end of the resistor and the end point at the other end (touching the edge of the surface on which you're defining the boundary).

Does that help at all, or did I miss your point?

 

[belma1511]

So I'm trying to simulate a 100Ω thin resistor placed between two quarter-wave transmission lines branches.
You can see a picture of it in the attachments.
Could you explain me in detail the steps of assinging this resistor?
I would appreciate your help

 

[psuclint]

From the diagram, I would create a thin rectangle (Draw menu -> Rectangle) between the two arms that the resistor connects. (Depending on whether the rectangle overlaps with the arms of the transmission line branches, you may need to do a subtraction so that they don't overlap - subtract a copy of the branches from the rectangle.) Then select your rectangle, right-click -> Assign Boundary -> Lumped RLC. Check the resistance box and enter your resistance of 100ohms. Then in the Current Flow Line drop-down, select new line, then click in the middle of one end of the rectangle, then click in the middle of the other end (roughly corresponding to the ends of the resistor in the diagram you showed above). Then click OK, and you should be good to go.

 

[YechielA]

You should understand that in the real world there should be a 0402 or a 0603 two square pads for the resistor, so that the RLC boundry condition should be placed in between these two pads on a surface connecting both ends.

Posted via Topify on Android

 

[belma1511]

Could you explain me what these square pads are and what is their purpose?
Also any idea which electrical length the 50Ω input transmission line should have?